thirdOrderLossFunction

open override fun thirdOrderLossFunction(x: Double): Double(source)

G3(x) = (1/6) * Emax(X - x, 0) * max(X - x - 1, 0) * max(X - x - 2, 0).

Accumulated from G2, as G2 is from G1. The third binomial moment of a binomial is C(n,3)*p^3, which is where the accumulation starts.